SLS 04: Thin cylinder under uniform radial pressure

Description

Handcalculation

$\Delta R=\frac{q \cdot R^2}{E \cdot e}=\frac{10kN/m^2 \cdot (1m)^2}{210 000N/mm^2 \cdot 0,02m}=0.002381mm$

$\Delta y=\frac{q \cdot R \cdot \nu \cdot L}{E \cdot e}=\frac{10kN/m^2 \cdot 1m \cdot 0.03 \cdot 4m}{210 000N/mm^2 \cdot 0,02m} = 0.002857mm$

Deformation $\delta_y$ in Diamonds

Point	Which result	Independent reference	Diamonds	Difference
Y=4m	Longitudinal deformation $\delta_y$	0,002857mm	0,002846mm	-0,71%
Y=2m	Radial deformation $\delta_x$ and $\delta_z$	0,002381mm	0,002364mm	-0,39%

Mécaniciens, S. F. D. (1990). Guide de validation des progiciels de calcul des structures: SSLS 06: cylindre mince sous pression radiale uniforme
Roark, R. J., & Young, W. C. (2002). Roark’s Formulas for Stress and Strain (7th edition, Table 13.1 case 1b). McGraw-Hill Companies.

Need Support?

Can't find the answer you're looking for? Don't worry we're here to help!