SLS 05: Thin cylinder under a uniform axial load

Description

Handcalculation

$\sigma_1=\sigma_{zz}=\frac{p}{e}=\frac{10kN/m}{0,02m}=5 N/mm^2$

$\Delta R=\delta_x=\delta_z=\frac{p \cdot \nu \cdot R}{E \cdot e}=\frac{10kN/m \cdot 4m \cdot 1m}{210000N/mm^2 \cdot 0,02m}=0,000 714mm$

$\Delta y=\delta_y=\frac{p \cdot L}{E \cdot e}=\frac{10kN/m \cdot 4m}{210000N/mm^2 \cdot 0,02m}=0,009524mm$

Deformation $\delta_y$ in Diamonds

Point	Which result	Independent reference	Diamonds	Difference
mid	stress $\sigma_zz$	0,5N/mm²	0,5N/mm²	0,00%
max	Longitudinal deformation $delta_y$	0,009524mm	0,009525mm	0,01%
max	Radial deformation $\delta_x$ and $\delta_z$	0,000714mm	0,000750mm	5,00%

Mécaniciens, S. F. D. (1990). Guide de validation des progiciels de calcul des structures: SSLS 07: cylindre mince sous charge axiale uniforme.
Roark, R. J., & Young, W. C. (2002). Roark’s Formulas for Stress and Strain (7th edition, Table 13.1 case 1a). McGraw-Hill Companies.

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