{"id":2436,"date":"2018-02-20T13:21:34","date_gmt":"2018-02-20T13:21:34","guid":{"rendered":"http:\/\/buildsoftsupport.com\/?post_type=ht_kb&p=2436"},"modified":"2024-08-21T07:09:57","modified_gmt":"2024-08-21T07:09:57","slug":"how-many-load-combinations-do-i-have","status":"publish","type":"ht_kb","link":"https:\/\/support.buildsoft.eu\/nl\/knowledge-base\/how-many-load-combinations-do-i-have\/","title":{"rendered":"How many load combinations do I have"},"content":{"rendered":"

\"n\" = the number of ‘dead’ loadgroups (for example: self weight, dead loads)<\/p>\n

\"k\" = the number of ‘life’ loadgroups (for example: life load A, wind, snow, temperature)<\/p>\n

The total number of load combinations in ULS FC according to EN 1990 [–] equ. 6.10 will be:<\/p>\n

\n

  <\/span>   <\/span>\"\[2^n \cdot (k \cdot 2^(^k^-^1^) + 1)\]\"<\/p>\n<\/p>\n

Example:<\/p>\n

\"\"<\/p>\n

\"n\" = 3, \"k\" = 5, total number of load combinations ULS FC according to EN 1990 [–] is:<\/p>\n

\n

  <\/span>   <\/span>\"\[2^n \cdot (k \cdot 2^(^k^-^1^) + 1)=2^3 \cdot (5 \cdot 2^(^5^-^1^) + 1)=648\]\"<\/p>\n<\/p>\n

Remarks:<\/p>\n